Chuck Oates
OCCC APPM 1313
DRAFT Version 0.02
Roman Numerals
An Intuitive Approach
Worksheets 12 and
13 in the worksheet packet at chuckoates.com , URLs
http://chuckoates.com/MathHC/Worksheets/Worksheet-12.jpg
and http://chuckoates.com/MathHC/Worksheets/Worksheet-13.jpg, present the Roman numeration system in a fairly
formal way. Let’s have a look at that
system from a bottom-up, somewhat intuitive approach.
Let’s count up
from one, very much as we did when we learned the decimal place value
system.
The Roman system
represents numbers less than ten with the symbols I = 1 and V = 5. The first three numbers are quite easy.
1: I
2: II
3: III
At four, we’re
tempted to write IIII, but since this can’t go on forever and still be legible,
the Roman system used the form
4: IV (the symbol for one appears before
the symbol for five)
meaning “one
subtracted from five.” Things go pretty
much as expected from five through eight.
5: V
6: VI (five plus one)
7: VII (five plus two)
8: VIII (five plus three)
At nine, once again we encounter the “IIII”
problem and solve it pretty much the same way we did at four. We’ll need an extra pair of symbols,
X = 10 and L = 50 to go on to 100. (Notice that in our customary decimal place
value system, we just re-used the numerals “1” and “5” moved to the left one
place to represent 10 and 50. The Romans
didn’t have this luxury!)
9: IX (one subtracted from ten)
10: X
11: XI (ten plus one; compare this with nine,
above)
12: XII
13: XIII
Here we are again with the “IIII”
problem. We’ll solve it the same way.
14: XIV
15: XV
16: XVI
17: XVII
18: XVIII
The “IIII” problem strikes again.
19: XIX (ten with nine written after it)
20: XX
21: XXI
22: XXII
Things go on up in a similar pattern
between tens (10, 20, 30, …), so now let’s count by tens, and you can fill in
the numbers in between.
30: XXX
40: XL (the “XXXX” problem is solved using
the same trick we used
before at four,
IV)
50: L
60: LX
70: LXX
80: LXXX
Now that we’re up near 100, we’ll need to
introduce the next “decade” of symbols, C = 100 and D = 500.
90: XC (the “XXXX” problem is solved here again
using the trick we
used before at
nine, IX)
100: C
110: CX
120: CXX
130: CXXX
140: CXL (one hundred plus forty)
150: CL
Things go up by tens pretty much as before
at 50, 60, 70, 80, and 90 at this point.
You can figure out the pattern easily.
Let’s count by hundreds now to see how that goes.
200: CC
300: CCC
400: CD (100 subtracted from 500 to keep from
writing “CCCC”)
500: D
600: DC
700: DCC
800: DCCC
We’re up near 1000 now, so we’ll need to
introduce the special symbol for 1000, M = 1000. That’s about as high as we’ll need to go.
900: CM (100 subtracted from 1000 to keep from
writing “DCCCC”)
1000: M
1100: MC
1200: MCC
1300: MCCC
1400: MCD (1000 plus 400)
1500: MD
1600: MDC (1000 plus 500 plus 100)
1700: MDCC
1800: MDCCC
1900: MCM (1000 plus 900)
2000: MM
2007: MMVII
That’s about as high as we’ll need to
count, since Roman numerals are seldom used for anything other than numbering
preface pages in books and disguising copyright dates on movies these days. You’ll still see them used on prescriptions
written using apothecaries’ units by private physicians for non-hospital
pharmacies, though.
With some study, the information above
should give you a pretty good feeling for how to convert our place value number
representations (90, 157, 2500) to their Roman equivalents (XC, CLVII, MMD).
Real Soon Now, I’ll add some examples of
conversions in the other direction, Roman to place value, otherwise known as
Roman to (westernized) Arabic numeration system conversions.
In the mean time,
more than you ever wanted to know about Roman numerals and the Roman numeration
system can be found at http://home.att.net/~numericana/answer/roman.htm.
Please e-mail me
at Chuck@ChuckOates.com if you find
errors in the above. It’s a draft
version, written quite late at night, and I’d be surprised if there weren’t a
few undetected problems remaining.